by skippy on March 15th, 2009

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If a 0.8 kg ball is dropped from a height of 9 meters, what is its kinetic energy when it hits the ground?

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by WarHorseLeBron on September 14th, 2010
Energy is energy.

There's no resistance. No energy transfer. So change in kinetic energy will be the same as the change in potential engergy, which is easier to calculate.

PE = mgh = 0.8*9.81*9 = 7.63 J
------------------------------------
To prove KE = PE...

KE = 1/2mv^2 = 1/2m(sqrt(2gh))^2 = 1/2m2gh = mgh
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If a 0.8 kg ball is dropped from a height of 9 meters, what is its kinetic energy when it hits the ground?

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