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by sassafrass on February 28th, 2009
let's see if I can do the first one on the fly:
factor out the 2m first:
2m(m^4 - 6m^2 + 9) Forget that m is to the fourth power since the second term is to the second power. You can factor the trinomial in the parenthessis just like a quadratic, but with m^2 as the variable, not simply m:
2m(m^2 - 3)(m^2 - 3) ... now, if you're really pedantic, you can factor the binomials as the difference of squares:
2m(m + SQRT(3))(m - SQRT(3)(m + SQRT(3))(m - SQRT(3))
and now, if you combine terms:
2m[(m + SQRT(3))(m - SQRT(3))]^2
I'll leave the next one to another lucky fellow
by sassafrass on March 4th, 2009
Oh, let's do the second one just for fun:
First factor out 5x^3y:
5x^3y(7y^3 - 12x)
Done.
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by Ombliss22 on September 25th, 2011
| 1 person likes this
Can you do this for me smallest to largest!! 0.3 , 0.109 , 0.1
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Math question found in +venture in math (s'pore)
by HANz318 on October 30th, 2011
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by naren.answers on October 19th, 2011
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MAth homework help in description below
by Anonymous on October 9th, 2011
| 1 person likes this
You're reading I need help on how to factor. can you answer this and explain to me how you did it? 2m^5-12m^3+18m. and this one confused me too 35x^3y^4-60x^4y. Don't worry I already turned in this assignment but did badly. I'm not cheating : )
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