by Satish_T on August 14th, 2011

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HOW WE CAN CALCULATE THE VELOCITY OF FLUID IF IT ACCLERATE FROM ZERO VELOCITY AND WE HAVE GIVEN ENERGY

t7 - 100% (2 votes) 100%

hgy - 0% (no votes) 0%

ytu - 0% (no votes) 0%

Yu - 0% (no votes) 0%

67 - 0% (no votes) 0%

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Answers. 3 helpful answers below.

by Crowsnest on August 14th, 2011
Boundary conditions:
Free, non viscous, fluid.

I'll try to play a little bit ....

May I?

Ohh thanks :-)

Lets give names:
E= energy
m= mass
v= speed
d= density
Q= volume
t= time

Then:

E= 1/2 m v^2 -------- d(E)= m v d(v). Energy changes, causes a change in momentum, looks logical.

m= Q x d; d(m)= d(Q) x d:

By neglecting the section of the element d(Q), I THINK it can be done: d(Q)= d(v)/d(t)

Then:
d(E)= d(v)/d(t) x d x v x d(v)

v d(v)^2= [d(E) d(t)]/d

Double integal at both sides:

1-) 1/2 v^2 d(v)= [E d(t)] /d
2-) 1/6 v^3 = (E t)/d + C

If for t=0 v=0 then C=0

v= CUBIC_ROOT ( 6Et/d)

Looks nice ¡ May be its even correct, Im not sure :-)
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- Thanks a lot for your "like" its important for me.
  
  Regards
  
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  by Crowsnest on August 15th, 2011
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by WarHorseLeBron on August 14th, 2011
This is a very stupid question. "67" is one of the available answers? Really?
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- May be she/her has already solved the question ;-)
  
  Regards
  
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  by Crowsnest on August 14th, 2011
- Or might have just copied the answer from textbook.:)
  
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  by engineer is Terminator on August 14th, 2011
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by Crowsnest on August 14th, 2011
Sorry but ......

What are the boundary conditions of that fluid ?
Comments
- This is his/her first question I guess and most of the questioners like this ask really silly things.
  
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  by engineer is Terminator on August 14th, 2011
- May be she/he "hears a bell anywhere, but doesn't know where"
  
  Anyway the question made me think ...
  
  Regards
  
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  by Crowsnest on August 14th, 2011
- Made me think too, but I avoided it due to lack of details and these guys don't come back to give clarification, but I thank you for answering it.
  You answer beholds a good point and someone searching for same type of answers on the internet, might see your answer and get the hint about boundary conditions and the other answer would lead him/her to the point where he/she desired to arrive at.
  
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  by engineer is Terminator on August 14th, 2011
- Thank a lot my friend. My answer as only been a Maths game. I'd be glad if it results useful for anybody.
  ABout the asker .... I think we're not going to read him/her again. I dont know why, but ..... it seems he/she was just playing on the net.
  
  Regards
  
  Report
  
  by Crowsnest on August 14th, 2011
- I feel the same way.My way to check this is, by looking at the person's profile.99% of time people who ask Science questions as their first question, don't return back, but answering those might help others.So, we have to keep the good work going.It's always nice to do that job with friends.
  
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  by engineer is Terminator on August 14th, 2011
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