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by illuminati on February 19th, 2009

illuminati

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The average atomic mass of zinc is 65.380 amu. There are only two isotopes in naturally occurring zinc: (63.92925 amu), and (71.92780 amu) Calculate the percent composition of naturally occurring zinc. Someone help me and explain how to find the solution

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  • by melencoly on November 24th, 2009

    melencoly

    I'm not going to solve it but instead show you how to do it.

    65.380=(m*63.92925 + n*71.92780)/(m+n)

    where m and n are expressed in percentages and m+n = 100

    so you have two equations and two unknowns. Should be simple enough to solve now

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You're reading The average atomic mass of zinc is 65.380 amu. There are only two isotopes in naturally occurring zinc: (63.92925 amu), and (71.92780 amu) Calculate the percent composition of naturally occurring zinc. Someone help me and explain how to find the solution

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